Class Aliases for Namespaces in OOP in PHP

Suppose we have two classes Data, belonging to different namespaces. Suppose in some class we need objects of both these classes:

/project/test.php<?php
  namespace Project;
  
  class Test
  {
    public function __construct()
    {
      $data1 = new \Core\Users\Data; // create an object
      $data2 = new \Core\Admin\Data; // create an object
    }
  }
?>

Suppose we decided to simplify class calls via the use command. In this case, we face a problem: both classes have the name Data, which means we will have a name conflict:

/project/test.php<?php
  namespace Project;
  
  // There will be a name conflict:
  use \Core\Users\Data; // connect the first class
  use \Core\Admin\Data; // connect the second class
  
  class Test
  {
    public function __construct()
    {
      $data1 = new Data;
      $data2 = new Data;
    }
  }
?>

To solve this problem, there is a special command as that allows you to assign the connected class a pseudonym - a name under which this class will be available in this file. Let's rename our Data classes:

/project/test.php<?php
  namespace Project;
  use \Core\Users\Data as UsersData;
  use \Core\Admin\Data as AdminData;
  
  class Test
  {
    public function __construct()
    {
      $data1 = new UsersData;
      $data2 = new AdminData;
    }
  }
?>
Задание 1

Simplify the following code using use:

php<?php
  namespace Project;
  
  class Test
  {
    public function __construct()
    {
      $pageController  = new \Resource\Controller\Page;
      $pageModel       = new \Resource\Model\Page;
    }
  }
?>
Задание 2

Simplify the following code using use:

php<?php
  namespace Project\Data;
  
  class Test
  {
    public function __construct()
    {
      $pageController  = new \Project\Data\Controller\Page;
      $pageModel       = new \Project\Data\Model\Page;
    }
  }
?>