Reference Parameters in PHP

It is possible to make a change to a function parameter lead to a change of the parameter outside the function. To do this, the function parameter should be declared as a reference:

php<?php
  function func(&$num)
  {
    $num = 2;
  }
  
  $num = 1;
  func($num);
  echo $num; // 2
?>

Задание 1

Correct the following code so that the variable changes inside the function:

php<?php
  $num = 1;
  
  function func($num)
  {
    $num++;
  }
  
  func($num);
  echo $num; // should output 2
?>

Задание 2

Correct the following code so that the array changes inside the function:

php<?php
  $arr = [1, 2, 3, 4, 5];
  
  function func($arr)
  {
    $arr[0] = '!';
  }
  
  func($arr);
  var_dump($arr);
?>