The map function for iterating objects in python

Let's say we have a function square for squaring numbers. And there is a list to the elements of which we need to apply this function:

pythondef square(num):
  return num ** 2

lst = [2, 3, 6, 8, 15]

In Python, to solve this problem, you can use a special function map. It takes as parameters a function and a list to which elements it should be applied. Let's use map to solve the example:

pythonres = map(square, lst)
print(res)

Each list, like any complex object, takes up a lot of space in Python's system memory. Therefore, to save resources, after executing the code, a special iterable map object will be returned instead of a new list:

python<map object at 0x000001F16674BA00>

Let's loop through it:

pythonfor el in res:
  print(el)

As a result, all elements of the new list will be displayed:

python4
9
36
64
225

To create a new list from a map object, you need to apply the list function to it:

pythonlst = [2, 3, 6, 8, 15]
res = map(square, lst)

The following list will be displayed as a result:

python[4, 9, 36, 64, 225]

Also, when working with the map function, you can specify a lambda function in the first parameter. Let's rewrite the previous example using a lambda function:

pythonres = map(lambda num: num ** 2, lst, lst)
print(list(res))

pythondef func(num):
  return num + 1

lst = [1, 2, 3, 4, 5]
res = map(func, lst)
print(list(res))

pythondef func(txt):
  return txt[::-1]

lst = ['123', '456', '789']
res = map(func, lst)
print(list(res))